6k^2-3=2k

Solution for 6k^2-3=2k equation:

6k^2-3=2k

We move all terms to the left:

6k^2-3-(2k)=0

a = 6; b = -2; c = -3;
Δ = b2-4ac
Δ = -22-4·6·(-3)
Δ = 76
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{76}=\sqrt{4*19}=\sqrt{4}*\sqrt{19}=2\sqrt{19}$
$k_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-2\sqrt{19}}{2*6}=\frac{2-2\sqrt{19}}{12}
$
$k_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+2\sqrt{19}}{2*6}=\frac{2+2\sqrt{19}}{12}
$